4  Financial Project Evaluation

For which of you, intending to build a tower, sitteth not down first, and counteth the cost, whether he have sufficient to finish it? Lest haply, after he hath laid the foundation, and is not able to finish it, all that behold it begin to mock him, Saying, This man began to build, and was not able to finish. Luke 14

Infrastructure takes money to build. Money pays for the people to plan and build projects including tradesmen, construction managers, and engineers. Money also buys building supplies, construction equipment and land on which the project is to be built. How can you know if the money you spend on a project will be worth it? If you have many different options, how can you decide which one to build? How can you deal with the fact that money changes value over time?

Private businesses will evaluate a construction project as to whether it can return a reasonable profit. Governments may choose to build a project that provides the most benefits for their citizens at the lowest cost. Either way, a well-informed business, non-profit organization, or government will conduct a financial analysis of a potential construction project before committing to it. In addition, a financial analysis can guide planners, engineers, and construction managers on the appropriate design, scope, timeline, and resulting costs of an infrastructure project.

Think

Many of the principles and techniques you learn in this unit can apply to your own life, despite the meaningful differences between running a government or business and running a home. President Gordon B. Hinckley cautioned,

I recognize that it may be necessary to borrow to get a home, of course. But let us buy a home that we can afford and thus ease the payments which will constantly hang over our heads without mercy or respite for as long as 30 years. … I urge you, brethren, to look to the condition of your finances. I urge you to be modest in your expenditures; discipline yourselves in your purchases to avoid debt to the extent possible. Pay off debt as quickly as you can, and free yourselves from bondage.

Important

Many of the terms we use in this unit are used casually or differently by individuals, businesses, and industries (Boyte-White 2024). In this class, we will try to be consistent with our use of these terms. As a professional, it will be your responsibility to understand how each term is defined when evaluating financial analysis of a project or when communicating your results to others.

If you are unfamiliar with a term, look it up! Or ask! There are many good credible resources online. For example, see the Investopedia Dictionary (Investopedia 2024) and the U.S. Consumer Financial Protection Bureau glossary (US CFPB 2024a).

As always, you should know definitions for the terms in bold.

4.1 Returns and ROI

Learning Outcomes
  • Calculate the returns for a single period project.
  • Calculate return on investment (ROI) for a single period project.
  • Discuss the benefits and risks of debt leveraging on ROI.

Whenever you have a financial project — this can be something as basic as a savings account or as complex and large as a multi-year heavy civil construction project — you hope that what you get out of the project will be worth at least as much as you put into it. After all, if you don’t get more money than you started with, why even do it? You might as well have put your money in a mattress.

What we put into a project is called its investment. What we get out of a project are called its returns. Mathematically, the returns are

\[ \mathrm{Returns} = \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale\ value} - \mathrm{Capital\ investment} \tag{4.1}\]

Each of these terms in Equation 4.1 deserves a definition.

  • Revenue is the money earned from operating the project.
  • Expenses is money spent during a project in order to operate it. This might include supplies, wages, and equipment repairs.
  • Financing are payments required by any loans associated with the project.
  • Taxes are payments to the government required as part of a project’s operations or profits.
  • Sale value is the money you make by selling the project, or could make by selling the project.
  • Investment is the money you spend to acquire the project, or to permanently improve it.

We will cover taxes later in Section 4.6.

Flipping Returns

You decide to “flip” a house in Provo. This means you want to buy a house, rennovate the house, and sell it for a higher value than you bought it for. If you buy the house for $400,000, spend $80,000 on renovations (a capital investment), and sell it for $600,000, what are your returns?


You have no revenue from operating this project, and no expenses or financing. We also haven’t covered taxes yet, so we’ll ignore that for now. Starting from Equation 4.1,

\[\begin{align*} \mathrm{Returns} &= \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale value} - \mathrm{Capital\ investment}\\ &= 0 - 0 - 0 - 0 + 600,000 - (400,000 + 80,000)\\ &= 120,000 \end{align*}\]

The returns of this project are $120,000.

Any positive return is better than a loss, but a small positive return on a massive investment would be disappointing. We need a measure that can normalize how well a project does relative to its investment. A measure the effectiveness of an investment is return on investment or ROI. This is simply the ratio of returns to investments, or

\[ ROI=\frac{\mathrm{Returns}}{\mathrm{Capital\ investment}} \tag{4.2}\]

We often describe ROI as a percentage.

Flipping ROI

For the house flipping project described in the previous example, what is the ROI?


We our returns were $120,000 on an investment of $480000 so the ROI is (using Equation 4.2)

\[\begin{align*} ROI&=\frac{\mathrm{Return}}{\mathrm{Investment}}\\ &=\frac{120000}{480000}\\ &= 0.25 \end{align*}\]

Or, an ROI of 25%.

ROI and winning / losing

Note that the capital investment is counted twice in the ROI formula: once in the denominator, and once again in the returns equation (Equation 4.1). This leads to some interesting observations:

  • A project with a 25% ROI means we grew our investment by 25%, which is in one year is much higher than the rate of inflation, or savings accounts, or even the average stock market. So this would probably be considered an excellent project. Even if you would be really disappointed to get 25% on an exam.
  • A project with a 100% ROI means that we effectively doubled our investment.
  • A project with a 0% ROI means that we didn’t make any money, but didn’t lose money either. Losing money would mean a negative return, and therefore a negative ROI.
Keeping the investment

What happens if you don’t sell the house at the end of the project?

When you make a capital investment you get to keep whatever you purchased, whether it’s a house or equipment or a piece of a company. Until you sell the investment you don’t know what its true value will be, but its value probably didn’t go to zero, and this value should be included in the project’s returns.

Maybe you have purchased an asset like stock in a company that always has a known value.

Returns on a stock

You purchased one share in the Caterpillar heavy equipment manufacturer in 2024 for $397. In October 2025, this stock was worth $500. What is your ROI?


Although you will not realize your returns until you sell the stock, you can still calculate a return on your investment to this point.

\[\begin{align*} \mathrm{Returns} &= \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale\ value} - \mathrm{Capital\ investment}\\ &= 0 - 0 - 0 - 0 + 500 - 397\\ &= 103 \end{align*}\]

\[\begin{align*} ROI&=\frac{\mathrm{Return}}{\mathrm{Investment}}\\ &=\frac{103}{397}\\ &= 0.259 \end{align*}\]

Public company stocks always have a known market price. The value of things like real estate or stock in a private company might be more hazy, but until you realize the price you can at least assume that you didn’t lose value, or you can make a guess at what the value of the property might be.

Returns without a sale

You invest $480,000 to buy and rennovate a house in Provo. you think that these improvements increased the value of the home to at least $500,000.


Although in this case the $500,000 is just an estimate, you can still calculate a prospective return on your investment.

\[\begin{align*} \mathrm{Returns} &= \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale\ value} - \mathrm{Capital\ investment}\\ &= 0 - 0 - 0 - 0 + 500000- (400,000 + 80,000)\\ &= 20,000 \end{align*}\]

\[\begin{align*} ROI&=\frac{\mathrm{Return}}{\mathrm{Investment}}\\ &=\frac{20,000}{480000}\\ &= 0.0417 \end{align*}\]

Of course, the question remains that if we thought the new value would be higher or lower, it might change whether we do the project in the first place.

For homework in this class, IF YOU ARE NOT TOLD WHAT THE NEW VALUE OF THE INVESTMENT IS, ASSUME IT DID NOT CHANGE.

Let’s explore the other parts of the Returns equation in Equation 4.1. If you have operating expenses or are collecting revenue from your project, you need to account for that in your calculations of the returns.

Flipping with Rent

You decide to rent the house in Provo out for a year after fixing it and before selling it. Your renters will pay $2000 per month, but you have to pay $400 per month in utilities. Additionally, your tenants inform you that a toilet backed up regularly and you have to pay $5000 to repair and clean the damage. What is the ROI for this project?


It is impossible to calculate the ROI without first calculating the returns using Equation 4.1. The renters bring revenue for each month, with expenses related to the utilities and the toilet repair.

\[\begin{align*} \mathrm{Returns} &= \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale\ value} - \mathrm{Capital\ investment}\\ &= 12\times2000 - (12 \times 400 + 5000) - 0 - 0 + 600,000 - (400,000 + 80,000) \\ &= 134,200 \end{align*}\]

The ROI can then be had using Equation 4.2

\[\begin{align*} ROI&=\frac{\mathrm{Return}}{\mathrm{Cost\ of\ Investment}}\\ &=\frac{134200}{480000}\\ &= 0.28 \end{align*}\]

So with an ROI of about 28%, it would be more profitable to rent for a year than to sell immediately (as in the previous example), assuming that you can get the same sale price.

Capital investment or expense?

Expenses and investments in a project each reduce the returns in Equation 4.1, so why does it matter where you put them? When you are calculating the taxable income on your project (see Section 4.6), you can often deduct expenses, but you cannot usually deduct investments. Where you put investments and where you put expenses also affects the ROI. In the prior example, the cleanup is an expense of operating the project.

Investments involve permanent improvements, and expenses are general tasks required to maintain. Installing a new roof is an investment, fixing a leak in a roof is an expense. That doesn’t mean expenses can’t be expensive!

What happens when you use debt to start a project? This will decrease the returns from the project, because you will have to pay interest to the person who lent you the money. But you won’t have to invest as much in the project to start with, because that money isn’t yours. This can substantially increase the profitability of the project. We will cover the details of interest in Section 4.2, but we will consider what happens to the project ROI here.

Flipping with Debt

You decide to take out a loan to purchase the house that you want to repair and then rent. The bank is willing to offer terms where you pay only 30% of the house price (a down payment) in exchange for a $21,000 financing fee. They then give you the money to buy the rest of the property, which you will pay back when you sell at the end of the year. Assume that you still rent the house and incur the same expenses. What is the ROI now?


Our investment changes because instead of paying for the entire house, we only pay for \(30\% \times \$400,000 = \$120,000\) of the purchase, plus the $80,000 it takes to repair the house. But we don’t make as much returns when we sell the house, because we have to pay back the \(70\% \times \$400,000 = \$280,000\) loan as well as the interest payment for how much of the money we borrowed.

\[\begin{align*} \mathrm{Returns} &= \mathrm{Revenue} - \mathrm{Expenses} - \mathrm{Financing} - \mathrm{Taxes} + \mathrm{Sale\ value} - \mathrm{Capital\ investment}\\ =& 12\times2000 - (12 \times 400 + 5000) - (280,000 + 21,000) - 0 + 600000 - (120,000 + 80000 )\\ =& 113,200 \end{align*}\]

This is much lower than we hadd previously. Let’s look at the ROI.

\[\begin{align*} ROI&=\frac{\mathrm{Return}}{\mathrm{Cost\ of\ Investment}}\\ &=\frac{113,200}{120,000 + 80,000}\\ &= 0.566 \end{align*}\]

This ROI of 56.6% is twice the ROI we saw before!

This process of using debt to increase the profitability of a project is called leveraging. There are of course pros and cons associated using debt in this way. The returns go down, meaning that doing one project with debt would be a little less profitable than doing one project without it. But because you have less of your own resources invested in that one project, you could maybe do two projects! In that way you can increase your total overall returns across for the same amount of investment. That’s one reason why ROI is a good measure.

The cons of using debt to finance a project come when the project is unsuccessful. What if you don’t find renters? Or the repairs cost $50000? In that case, you don’t just lose your investment; the bank loses theirs also and you might not be able to borrow again on advantageous terms.

4.2 Time Value of Money

Learning Outcomes
  • Describe why money in the future is worth less than money now.
  • Calculate equivalent future and present values using simple and compound interest, with different compounding rates.

Imagine you win a contest and are given two options. You can choose to collect your $1,000 prize today, or you can wait for ten years to get the same amount of money. Which option would you choose? There are at least three reasons you should take the money right away:

  • Risk There is a possibility that something bad could happen to your prize. Within the next 10 years, the company offering the prize could go bankrupt. Or you could die or become otherwise disqualified from claiming the prize.
  • Inflation Money loses value over time for a variety of reasons. $1000 will buy more goods and services now than it will in ten years.
  • Opportunity cost If you got the prize now, there are things you could do with it. You could spend the money on something that you would enjoy for the next ten years. You could also invest the money for ten years, during which time you would earn on that investment. Getting the prize later costs you these opportunities.

Money has value. Having money now is more valuable than having money in the future. This is called the time value of money. If I were to lend you money, I would want to receive not only the initial loan amount, but some payment to compensate me for the risk, inflation, and opportunity cost of making the loan. This payment is called interest. There are two basic methods for calculating interest:

  1. Simple interest loans require a defined interest payment on the principal of the loan, or how much the loan is for.
  2. Compound interest loans recompute interest along with the unpaid principal at a particular compounding rate.

If we have a simple interest loan, we can convert a present value of money \(P\) into a future value of money \(F\) with the formula: \[ F_\mathrm{simple}= P + P\times{i}\times{n} \tag{4.3}\] where \(i\) is the interest rate (usually percent per year) and \(n\) is the number of interest periods (usually years). In each year, we pay an interest charge \(P\times i\).

Warning

Interest rates are usually given in percentages (e.g., an interest rate of 12%), but should be used as decimal proportions in equations (e.g., \(i = 0.12\)).

Simple Interest

You borrow $50,000 to buy a truck with a simple interest loan and an annual interest rate of 10%. You will pay all the interest and the complete principal back at the end of the loan. How much do you owe at the end of the 5 year loan?


In each period, the amount of interest we accrue is the \(P\) times the rate \(i\). We use the Equation 4.3 to calculate the total amount we pay.

\[\begin{align*} F_\mathrm{simple} & = P + P\times{i}\times{n}\\ &= 50,000 + 50,000 (0.10) (5)\\ &= &75,000 \end{align*}\]

Table 4.1 shows how the simple interest accrues in each period, with the interest on the principal adding to the loan balance but not to the principal itself. So the interest in each period is simply \(P \times i\)

Table 4.1: Loan Balance for 5-year Simple Interest Loan
Year Principal Interest Loan Balance
0 50000 0 50000
1 50000 5000 55000
2 50000 5000 60000
3 50000 5000 65000
4 50000 5000 70000
5 50000 5000 75000

So, the total payoff amount for the truck loan is $75,000.

While simple interest loans are easy to calculate and understand, almost all investments and loans use compound interest. The amount we will pay in the future \(F\) on a loan requires a little derivation. After one period, the compound interest formula looks just like the simple interest one, \[ F = P + P\times i=P(1+i) \tag{4.4}\] If we have two periods, then we need to take the value from Equation 4.4 and multiply it by \(i\), plus add another Equation 4.4 again for the new interest we add in year 1 \[ F = P(1+i)+P(1+i)i=P(1+i)(1+i)=P(1+i)^2 \tag{4.5}\]

If we keep doing this for \(n\) periods, we can derive a general equation \[ F = P(1+i)^n \tag{4.6}\]

Compound Interest

You borrow $50,000 to buy a truck with a compount interest loan, compounding annually at 10% per year. You will pay the interest and the complete principal back at the end of the loan. How much do you owe at the end of the 5 year loan?


Let’s use Equation 4.6. We want the value we will pay in the future \(F\), and we have \(P=50000, i = 0.1, n=5\):

\[\begin{align*} F &= P(1+i)^n\\ & = 50000 (1 + 0.1)^{5}\\ & = 80,526 \end{align*}\]

This is the payoff for the truck loan if we assume compounding interest.

Table 4.2 shows the progress of this compounding. Effectively, the primary difference is that we calculate the interest based not on the principal alone but on the entire loan balance, which has the previous periods’ interest added into it. So the interest accruing in year 3 is \[I_3 = 60,500 * 0.1 = 6050.0\]

Table 4.2: Loan Balance for 5-year Compound Interest Loan
Year Principal Interest Loan Balance
0 0 0.0 50000.0
1 50000 5000.0 55000.0
2 50000 5500.0 60500.0
3 50000 6050.0 66550.0
4 50000 6655.0 73205.0
5 50000 7320.5 80525.5

We therefore will pay a total of $80,525.50, or about $5,500 more than we did with the simple interest loan.

One consideration with compound loans is the compounding frequency, or how often the interest is applied into the total amount owed. Usually, the compounding frequency and the interest rate and the number of periods will all be the same: that is, \(n\) will be in years and \(i\) will be in percent per year, with annual compounding.

But that might not always be the case! Sometimes loans could compound more frequently than once per year. Many mortgages, for example, give a nominal interest rate per year, but actually compound monthly. In this case, Equation 4.6 becomes

\[ F=P[1+(i/k)]^{nk} \tag{4.7}\]

with \(k\) the number of compounding periods in each \(n\). You can see how this works: the nominal interest rate is divided across \(k\) periods, but the total number of periods multiplied to \(nk\). \(i/k\) is referred to as the periodic interest rate.

Compounding frequency

The compounding frequency has a pretty important role in how much the loan is worth in the future. Let’s look at three situations where $1000 is loaned at 10% interest (\(i = 0.1\)) for ten years.

  • Yearly compounding (\(k\)=1): \(\$1000[1+(0.1/1)]^{(1*10)}=\$2593.74\)
  • Monthly compounding (\(k\)=12): \(\$1000[1+(0.1/12)]^{(12*10)}=\$2707.04\)
  • Daily compounding (\(k\)=365): \(\$1000[1+(0.1/365)]^{(365*10)}=\$2717.91\)

Figure 4.1 shows the growth in the loan amount at each compounding period for different compounding frequencies. There is obviously a big difference between annual and monthly compounding, but there isn’t that much difference between monthly and daily, or daily and even hourly compounding. This suggests that there is a limit to this function as \(k\) increases.

Figure 4.1: Growth of loan value at different compounding frequencies.

It turns out that if you take the limit \(\lim_{k\to\infty} F=P[1+(i/k)]^{nk}\) you can derive the equation for continuously compounding interest, \[ F=Pe^{in} \tag{4.8}\]

Using our new equation, we can find out how much money we will have after 10 years of continuously compounding the interest from our $1,000 invested at an interest rate of 10%.

  • Continuously: \(\$1000*e^{(0.1*10)}=\$2718.28\)

Notice that this value isn’t significantly more than the amount of interest earned by compounding the interest daily. As the number of compounding periods continues to increase, the interest earned in each period increases by a diminishing amount. However, remember that even when the difference may be small, the more frequent the compounding period, the more interest is generated.

You may see bank advertising their savings accounts with an Annual Percentage Yield (APY) instead of an interest rate (Chen 2024). The APY is an annual interest rate compounded once per year that would give you the same returns as the actual or periodic interest rate using the compound frequency of the bank.
So after one year (\(n = 1\)), the future value of the investment over 1 year using the APY and the periodic interest rate and compounding frequency should be equal to each other:

\[\begin{align*} F_{\mathrm{annual}} &= F_{\mathrm{actual}} \\ P(1+APY)^n &= P(1+i/k)^{nk} \\ P(1+APY)^1 &= P(1+i/k)^{k*1} \end{align*}\] \[ APY = (1+i/k)^k -1 \tag{4.9}\]

The APY allows investors to compare returns from investments that have different compound periods.

APY Example

A savings account has a nominal interest rate of 4.25%, and is compounded monthly. What is the APY?


Using Equation 4.9,

\[\begin{align*} \mathrm{APY} &= (1+i/k)^{k}-1 \\ &= (1+\frac{0.0425}{12})^{12}-1 \\ &= 0.0433\\ &= 4.33\%\\ \end{align*}\]

Terms for \(i\)

Depending on the context of the problem, the term \(i\) may be described as an interest rate, a yield, or a discount rate. The term “discount” is used because when we calculate how much future money is worth in the present, we have to “discount” it for risk, opportunity cost, and inflation.

The term “inflation rate” is not generally appropriate for \(i\) on its own, because this would ignore the opportunity cost and risk aspects of the time value of money. But if you have no other options for investing and the risk is very low, then \(i\) and inflation rates can be very similar. During economic recessions the yield on US Treasury Bonds is often close to the inflation rate, because the US Government is seen as a low-risk investement, and other options in the economy are less attractive.

4.3 Annuities and Gradients

Learning Outcomes
  • Calculate equivalent future and present values for uniformly repeating (annuity) and uniformly increasing (gradient) cash flows.
  • Calculate equivalent values using equations, factor tables, and software functions.

In Section 4.2, you learned how to convert present values of money into future values of money and vice versa. But there are other ways of representing cash flows. Consider the following questions:

  • How can I convert the present cost of a home into a monthly payment that I can afford over the next 30 years?
  • If I have a piece of equipment that generates an income of $10,000 per year, what should I sell this equipment for now?
  • If I want to buy a $400,000 crane for my business in five years, how much should I save each year?

All of these questions involve transforming a present value \(P\) or a future value \(F\) into an equivalent uniform value. Because the periods we use are often years, we often call this annual uniform value an annuity, \(A\).

Let’s do a short derivation to calculate the \(A\) needed to equal a future value \(F\). If there is only one period, then the derivation is easy and \(F = A\). If it takes two periods, then the equation is \(F = A + A*(1 + i)\) because we have to discount the value of the second period’s payment. If you do this for \(n\) periods (see the full derivation in the callout below), you get

\[ F = A*\frac{(1 + i)^n - 1}{i} \tag{4.10}\]

Extending the full series \(n\) times gives you this summation.

\[\begin{align} F &= A + A*(1 + i) + A* (1 + i)^2 + \ldots + A*(i+1)^{n-1} \\ &= \sum_{j = 0}^{n -1} A ( 1 + i)^j\\ \end{align}\] If you multiply both sides of this equation by \((1 + i)\) this changes the index on the summation to have \(j\) start at 1 and go all the way to \(n\) \[\begin{align} F(1 + i) &= \sum_{j = 1}^n A ( 1 + i)^j \\ \end{align}\] Let’s subtract the equation for \(F= \sum_{j = 0}^{n -1} A ( 1 + i)^j\) from both sides of this new equation, which will allow us to subtract out everything except the first value of the first summation, and the last value of the second summation. We can then solve the equation for \(F\),

\[\begin{align} F(1 + i) - F &= \sum_{j = 1}^{n } A ( 1 + i)^j - \sum_{j = 0}^{n-1} A ( 1 + i)^j \\ &= \left[A ( 1 + i)^n + A ( 1 + i)^{n-1} + \ldots + A ( 1 + i)^1\right] - \\ &\quad \left[A ( 1 + i)^{n-1} + A ( 1 + i)^{n-2} + \ldots + A ( 1 + i)^0\right] \\ F+ Fi - F &= A*(1 + i)^n - A\\ Fi &= A*[(1 + i)^n - 1]\\ F &= A*\frac{(1 + i)^n - 1}{i} \end{align}\]

\(F\) given \(A\)

If you deposit $10,000 each year into an account earning 5% interest, how much will you have after 20 years?


In this problem, we are given a uniform value \(A\) and need to find an equivalent future value \(F\). This is what Equation 4.10 does,

\[\begin{align} F &= A*\frac{(1 + i)^n - 1}{i} \\ F &= 10,000*\frac{(1 + 0.05)^20 - 1}{0.05} \\ &= 330,660 \end{align}\]

Note that the number of dollars we deposited is \(A * n\) or 200,000. But because the dollars we deposited early accumulated interest each year, the total value of the account is much more than the number of dollars deposited.

To turn a future value into an equivalent annuity, we just take the inverse.

\[ A=F*\frac{i}{(1+i)^{n}-1} \tag{4.11}\]

We could also derive an equation to convert a uniform repeating value into its present equivalent value P, but we will skip that derivation here because it’s very similar to the one we just did. The equation to convert \(A\) to \(P\) is:

\[ P=A*\frac{(1 + i)^n -1}{i (1 + i)^n} \tag{4.12}\] and for \(P\) to \(A\):

And from \(P\) to \(A\) is of course the inverse of that: \[ A=P*\frac{i ( 1 + i) ^n}{(1 + i)^n - 1} \tag{4.13}\]

This last Equation 4.13 is the equation that a bank will use to figure out what the monthly or annual payment is for a loan with a periodic pay back period. In this case the principal of the loan is the present value \(P\), and you need to repay the loan with an equivalent uniform payment \(A\).

A from P

You need to get a loan to buy a new warehouse for your construction supply business. The warehouse has a listed price of $1.2 million, and you can get a 4% per year loan which you will pay back with annual payments over 10 years. What is the payment?


In this case, we need to find a uniform value \(A\) given a present value \(P = 1.2\) million. We also have given \(n=10\) and \(i=0.04\) So we need to use Equation 4.13:

\[\begin{align*} A&=P*\frac{i ( 1 + i) ^n}{(1 + i)^n - 1}\\ &=1.2\times 10^6 *\frac{0.04 ( 1 + 0.04)^{10}}{(1 + 0.04)^{10} - 1}\\ &=147,949 \end{align*}\]

So we need to pay 147,949 dollars each year. Note that that total number of dollars we pay is 1,479,491, but because the dollars at the end of the period are worth less than the dollars at the beginning, we need to pay more of them to make the amounts equal.

As in Equation 4.7, we can convert nominal discount rates given in percent per year to use different compounding periods by dividing \(i/k\) and \(n*k\). This is pretty common, because many loans for things like cars and homes are repaid with monthly compounding interest and monthly payments.

Monthly payments

You are interested in buying a $400,000 home, and have been offered a mortgage loan that compounds monthly with a 6.25% annual interest rate. What is the monthly payment if you pay off the loan in 30 years?


We have been given \(P=400,000\), \(i=0.0625\), \(n=30\) and \(k=12\) for the monthly compounding. We need to find \(A\). So we need to start with Equation 4.13, but adjust it so that each \(i\) and \(n\) are adjusted by \(k\),

\[\begin{align*} A &=P*\frac{i/k ( 1 + i/k) ^{n*k}}{(1 + i/k)^n - 1}\\ A &=400000*\frac{0.0625(1+0.0625/12)^{30 * 12}}{(1+0.0625/12)^{30 * 12}-1}\\ A &= 2,463 \quad\textrm{dollars\ per\ month}\\ \end{align*}\]

This value is what it takes to turn a uniform monthly payment over the next 30 years into an equivalent present value.

Loan Interest

When you are repaying a loan, you have to pay back the principal on the loan while also paying the interest that the loan will accrue. Separating interest and principal payments is important for reasons that we will talk about more in Section 4.6 — essentially, money spent on interest payments is often deducted from taxes, so it can affect your project returns in Equation 4.1.

With each payment on a loan, you pay off all the interest that accrued that month first. So, in the first month when you owe $400,000, your interest contribution is \[\begin{align*} \mathrm{Monthly\ Interest}_1 &=400000*0.0625/12\\ &= 2,083 \quad\textrm{dollars}\\ \end{align*}\] leaving \(2,463 - 2,083 = 380\) as a payment that reduces your principal. In the second month, you calculate the interest payment from the remaining principal. As time goes by, the amount you pay to interest goes down, and the amount you pay to your principal goes up. Showing this is left as an exercise.

In most of our equivalence functions we have looked at, we assume some project end-point \(n\) time periods in the future. But what about the equivalent present value of a perpetual benefit? Like, what if a project that generates annual uniform benefits \(A\) is meant to last forever?

Consider Equation 4.12, as \(n\) gets really big

\[\begin{align*} P&=A*\frac{(1 + i)^n -1}{i (1 + i)^n}\\ &=A*\frac{(1 + i)^\infty -1}{i (1 + i)^\infty}\\ &=a*\frac{1}{i}\frac{(1 + i)^\infty -1}{(1 + i)^\infty}\\ &=a*\frac{1}{i}\frac{\infty - 1}{\infty}\\ \end{align*}\]

Because \(\infty-1 \approxeq \infty\), and \(\infty/\infty = 1\), this equation reduces to a simple long-run equation,

\[ P=\frac{A}{i} \tag{4.14}\]

It turns out that it doesn’t even have to infinite timelines to get to this point. With high values of \(i\) (like 15%), this simplification is reasonably accurate in as little as 25 years.

Long-run benefits

Your state is permanently setting aside land for a new state park. You estimate that preserving this land will be worth $100,000 each year. Using a discount rate of 8%, what is the present value of this action?


Because the benefits are permanent, we can use Equation 4.14.

\[\begin{align} P&=\frac{A}{i}\\ &=\frac{100,000}{0.08}\\ &= 1,250,000 \end{align}\]

4.3.1 Gradients

We have talked about repeating uniform value?. But what about a payment or cost that increases its value over time by a uniform amount? For instance, you expect that maintenance costs on a machine will increase each year, or you expect that a business line will grow, bringing in more revenue.

A uniformly increasing money flow is called a gradient, and we will represent this with the letter \(G\)[^financial-4]. Uniformly increasing means that if \(G = 100\), then the value of this gradient in year 1 is 0, but it increases by 100 in each subsequent year as \(G_1 = 0, G_2 = 100, G_3 = 200, \ldots, G_n = (n-1)*G\).

The formulas to convert a uniform increasing value \(G\) to a present value \(P\), a future value \(F\), or a uniform value \(A\) are:

\[ P=G*\left[\frac{(1+i)^{n}-1}{i^2(1+i)^{n}}-\frac{n}{i(1 + i)^n}\right] \tag{4.15}\]

\[ F=G*\left[\frac{(1+i)^{n}-1}{i^2}-\frac{n}{i}\right] \tag{4.16}\]

\[ A=G*\left[\frac{1}{i}-\frac{n}{(1+i)^n-1}\right] \tag{4.17}\]

Example

Maintenance on an old machine is $100 this year but is expected to increase by $25 each year thereafter. What is the present worth of five years of maintenance? Assume a discount rate of 10%.


This is an interesting problem because it involves both an annuity ($100 per year) and a gradient of $25 each year. We could draw a diagram of these cash flows as

Example of annuity and gradient

We can then calculate the present value of each element separately and add them together. Converting the gradient \(G = 25\) to its present value, \[\begin{align*} P&=G*\left[\frac{(1+i)^{n}-1}{i^2(1+i)^{n}}-\frac{n}{i(1+i)^{n}}\right]\\ &=25*\left[\frac{(1+0.1)^{5}-1}{(0.1)^2(1+0.1)^{5}}-\frac{5}{0.1(1+0.1)^{5}}\right]\\ &=172\\ \end{align*}\]

and converting the annuity \(A = 100\) to its present value, \[\begin{align*} P&=A*\frac{(1+i)^{n}-1}{i(1+i)^{n}}\\ &=100*\frac{(1+0.1)^{5}-1}{0.1(1+0.1)^{5}}\\ &=379 \end{align*}\]

meaning that we have a total present value of $551

4.3.2 Calculation Shortcuts

It is important to know that the equations we have discussed so far exist, and that they are not magical constructs banks designed to part you from your money. But the equations themselves are often unwieldy and impractical, and they are certainly difficult to remember.

Notice though that each equation we have looked at is the product of a scalar (\(A\), \(F\), etc.) and some factor of the interest rate and the time period. This means we could create a table that contains the factors for different interest rates and periods. A partial table for 2% discount rates is in Table 4.3, and a complete set of tables are in Appendix A. The way to read these tables is as follows:

  1. Identify the table for the discount rate you are given.
  2. Determine which column of factors you need. You read \(F/P\) as “\(F\) given \(P\)”, so this is your column if you have been given a present value and wish to find the future value.1
  3. Find the row in the table for the given number of periods. If \(F/P\) is your column and the number of time increments is 5, your value is 1.1041.
  4. Multiply the given value by the factor from the table. Keeping with the same example, if you were given 1,000 dollars for \(P\), you multiply it by 1.1041 to find \(F\) = 1,104.10 dollars.
Table 4.3: Factor Table: i = 2.00%
n P/F P/A P/G F/P F/A A/P A/F A/G
1 0.9804 0.9804 0.0000 1.0200 1.0000 1.0200 1.0000 0.0000
2 0.9612 1.9416 0.9612 1.0404 2.0200 0.5150 0.4950 0.4950
5 0.9057 4.7135 9.2403 1.1041 5.2040 0.2122 0.1922 1.9604
8 0.8535 7.3255 24.8779 1.1717 8.5830 0.1365 0.1165 3.3961
10 0.8203 8.9826 38.9551 1.2190 10.9497 0.1113 0.0913 4.3367
25 0.6095 19.5235 214.2592 1.6406 32.0303 0.0512 0.0312 10.9745
50 0.3715 31.4236 642.3606 2.6916 84.5794 0.0318 0.0118 20.4420
Example

You will need $10,000 in 5 years, and you can invest at 2% interest.

  1. How much do you invest now if you invest it all at once?
  2. How much would you invest each year if you did annual deposits?

Part a You wish to find the present value \(P\) given a future value \(F\), so you want the \(P/F\) column. The factor for this column in the 2% table at 5 years is 0.906, so you need to invest \[\begin{align*} P &= F * P/F(0.02, 5)\\ P &= 10,000 * 0.906\\ &= 9,057\mathrm{\ dollars} \end{align*}\]

Part b The second half of the question asks us to find the equivalent *annuity \(A\) given a future value \(F\), so we look up the \(A/F\) factor, which is 0.192.

\[\begin{align*} A &= F * A/F(0.02, 5)\\ A &= 10,000 * 0.192\\ &= 1,922\mathrm{\ dollars\ per\ year}\\ \end{align*}\]

The factor table method is easy and helps to train you to think about what is happening. But it is slow when you have repeated calculations, which is common for large projects. In practice, you will probably use functions that pre-exist in Excel, Google Sheets, or another software application. For example, the Excel FV() function will compute the future value \(F\) of a cash flow given either an present value \(P\) or a uniform flow \(A\).

FV(rate, number_of_periods, payment_amount (A), [present_value (P)])

If you are going to give a present value and not an annuity, you leave the payment_amount field blank. That means, the FV function works both as Equation 4.6 and also as Equation 4.10. The results and use of this function are shown in Figure 4.2. Table 4.4 provides a lookup table correlating the factor tables in Table 4.3 with the Excel and Google Sheets function equivalents.

Figure 4.2: Excel FV function in use.
Table 4.4: Factors and Spreadsheet Functions
Factor Excel / Sheets Function
P/F PV(i, n, ,F)
P/A PV(i, n, A)
P/G Not included
F/P FV(i, n, , P)
F/A FV(i, n, A)
A/P PMT(i, n, P)
A/F PMT(i, n, , F)
A/G Not included

Sometimes you need to do an analyis that neither Excel nor the factor tables are well-suited for. Or, you might realize that Excel is poorly suited to most serious work. In this case, you may want to write your own functions in the software environment that you prefer. For example, we can write an R function for Equation 4.7 that converts \(P\) to \(F\), and then use that function to compute the future value for a strange loan that compounds 20 times per year.

#' Function to change P to F
#' @param P Present value
#' @param i Discount rate
#' @param n Number of periods
#' @param k Compounding iterations per period, default is 1
#' 
#' @return Future value F
ptof <- function(P, i, n, k = 1){
  P * (1 + (i / k) )^(n * k)
}

# 1000 for ten years at 7.5%, compounding 20 times per year
ptof(P = 1000, i = 0.075, n = 10, k = 20)
[1] 2114.032

The python code for the same function is here:

def ptof(P, i, n, k=1):
  """
  Function to convert P to F

  Parameters
  ----------
  P : float
      Present value
  i : float
      discount rate per period
  n : int
      number of periods
  k : int
      number of compounding events per period
  
  Returns: 
    float: The future value of the money flow.
  """
  P * (1 + (i / k) )^(n * k) 
Which method should I use?

For short homework problems and exam questions, we strongly recommend that you use factor tables. Write out what you are trying to find, what you have, and the factor you need to convert one to the other. So, if you are given an annuity \(A\) and need to find a present value \(P\), write out \[ P = A * P/A(i, n) \] and look up the appropriate factor.

For long homework problems where you may have to construct a spreadsheet with dozens of calculations, you should use the spreadsheet functions available to you.

You won’t have to write your own R or python functions in this class, but knowing that you can might be useful later in your career.

4.4 Net Present Value

Learning Outcomes
  • Calculate the net present value (NPV) of a complex cash flow.
  • Draw a cash flow diagram for a project.

In Section 4.2 and Section 4.3, we discussed how to calculate the present value of a cash flow, whether that flow was a single future value (\(F\)), a series of uniform values (\(A\)), or uniformly increasing (\(G\)) future values.

This is powerful because it allows us to translate complex cash flows defined with different interest rates and time frames into an equivalent present value. Recall the returns equation we developed back in Equation 4.1, but now let’s look at it with multiple years so that we can accommodate the time value of money.

As we have talked previously, the reason to invest in a projects is to receive a return of benefits. If you are a developer, you want to build something that will generate income justifying the cost of construction. If you are building public infrastructure, the benefits might not be economic (although they could be). We will now consider definition of returns that considers the time value of money.

To do so, we need to be more precise about the timing of the returns. We will use the definition of returns in Equation 4.1, but with a wrinkle to spread the returns across multiple years.

\[ \mathrm{Returns}_t = \mathrm{Revenue}_t - \mathrm{Expenses}_t - \mathrm{Financing}_t - \mathrm{Taxes}_t + \mathrm{Sale\ value}_t - \mathrm{Capital\ investment}_t \tag{4.18}\]

Where

  • \(t\) is the years of analysis
  • Revenue is the money earned from operating the project in the year \(t\).
  • Expenses is money spent during a project in order to operate it in the year \(t\). This might include supplies, wages, and repairs.
  • Financing are payments required by any loans associated with the project in the year \(t\).
  • Taxes are payments to the government required as part of a project’s operations or profits.
  • Sale value is the money you make by selling the project’s assets in the year \(t\). If you still own an asset at the end of the project, you would use the value you could make by selling the the asset, but only in the final year.
  • Investment is the money you spend to acquire the project, or to permanently improve it, in the year \(t\).

When Equation 4.18 is calculated over the lifetime of the project, we obtain the earlier Equation 4.1. But that equation doesn’t consider that the positive returns at the end of a project are worth less than returns at the beginning, because of the time value of money.

Multiple year returns on a house flipping project

You purchase a house in Provo for $400,000 and invest $80,000 in repairs. You buy the house with a loan for 70% of the purchase price, at 3% annually compounding interest with a 5 year term (meaning that you own the entire home after five years). You then rent it out for five years, with a tenant paying $2000 per month, but you have to pay $400 per month in utilities. In year three you have to pay $5000 to repair and clean the damage from a toilet that backed up regularly. After five years, you sell the house for $700,000.

What are the returns on this project in each year?


Let’s handle each part separately. For revenue, you have $2000 per month for 12 months each year, so the annual revenue is

\[\mathrm{Revenue}_t = 2,000 * 12 = 24,000\]

The expenses each year are the utilities of $400 per month, plus the repair in year 3.

\[\mathrm{Expenses}_t = 400 * 12 = 4,800\] \[\mathrm{Expenses}_3 = 400 * 12 + 5,000 = 9,800\]

The financing payments are going to be what you need to pay as an annuity on your five year, 3% loan for 70% of the house. We can get this with Equation 4.13 or the appropriate factor,

\[\begin{align*} A &= P * A/P(i, n)\\ &= (0.7 * 400,000) * 0.218 \end{align*}\]

The capital sale is for the entire 700,000 purchase because by then you will have paid off your loan. The investment, however, is only for 30% of the 400,000 plus the 80,000 you invested. By convention, we put the investment in year 0, because we won’t discount the payment at all.

The returns in each year are the sum of all of these columns,

Table 4.5: Multiple Year Returns
year revenue expenses finance sale investment returns
0 0 0 0.00 0e+00 2e+05 -200000.00
1 24000 4800 61139.28 0e+00 0e+00 -41939.28
2 24000 4800 61139.28 0e+00 0e+00 -41939.28
3 24000 9800 61139.28 0e+00 0e+00 -46939.28
4 24000 4800 61139.28 0e+00 0e+00 -41939.28
5 24000 4800 61139.28 7e+05 0e+00 658060.72

So for most years, the project brings in negative returns. But in the last year it brings a large positive return. Is this a good project?

Once you have the annual project returns, you need to bring those returns into the present so that you can compare earnings on an equal footing. The total value of all project returns in present worth is called the Net Present Value of the project. If the NPV is positive, then the project will result in a positive return on investment. If it is negative, then the project will lose money over its life. The equation for the NPV is just the sum of each year’s returns, converted to a present value using a discount rate, \[ NPV=\sum_{t=0}^{n} \frac{R_t}{(1+i)^t} \tag{4.19}\]

where

  • \(R_t\): net returns at time \(t\)
  • \(i\): discount rate
  • \(t\): period of time

Note that the \(1/(1+i)^t\) is the same as Equation 4.6, or the equivalence function to bring a future value to the present.

Multi-year flipping

What is the NPV of the Provo house flip in the previous example if your discount rate is 8%?


For Year 1, the project returns were $41,939.28. We need to bring this into the present by using Equation 4.6,

\[\begin{align*} R_1 &= F / (1 + i)^n\\ &= 41939.28 / (1 + 0.08)^1\\ &= 38,833\\ \end{align*}\]

We can repeat this for each year, and sum the present values.

year returns PV
0 -200000.00 -200000.00
1 -41939.28 -38832.67
2 -41939.28 -35956.17
3 -46939.28 -37261.91
4 -41939.28 -30826.62
5 658060.72 447865.07

The NPV of this project is 104,988, meaning that doing the project is worth a positive value of 104,988 given an 8% discount rate.

It turns out it doesn’t really matter whether we first compute the net returns in each year and then transform these into present values, or if we first transform into present values and then add them up. The first method works better for complex projects, but the second might make more sense for simpler projects.

NPV on a basic cashflow

You buy a truck for $100,000, and plan to spend $15,000 per year on gas, insurance, and maintenance for six years. At the end of that period, you hope to sell the truck for $30,000. What is the NPV of this purchase if you have a 8% discount rate?


We are given the initial cost of the truck as a \(P\), the annual costs as \(A\), and the future value of the truck as \(F\). We can calculate the NPV by converting each of these flows into a present value using an appropriate factor and then adding them together:

\[\begin{align*} NPV &= P + A * P/A(8\%, 6) + F * P/F(8\%, 6) \\ &= (-100000) + (-15000) * (4.62) + (30000) * (0.63)\\ &= -150,438\\ \end{align*}\]

Note how in house flipping example, the bank issued a loan at an interest rate of 6%, but the NPV used a discount rate of 8%. This brings up the question of what discount rate should be used in NPV calculations, and how this discount rate is determined. Recall that the discount rate has to account for:

  • Risk: when you lend money, it might not always come back
  • Inflation: money will be worth less in the future
  • Opportunity Cost: you might be able to do something else with your money

Different people and organizations have different time values of money based on their priorities, standards, and perceptions of the world. For example, investors will expect higher returns on more risky investments, and larger investors might not want to take on smaller projects. Either way, they will use a higher discount rate in their analysis. The disount rate that a company uses in its NPV analysis is called its Minimum Acceptable Rate of Return.

Flipping with a higher MARR

Your company has set a MARR of 14% for its projects. What is the NPV of the house flipping project?


Everything stays the same, except now we are using a discount rate of 14%. In year I1, the project returns were $41,939.28. We need to bring this into the present by using Equation 4.6,

\[\begin{align*} R_1 &= F / (1 + i)^n\\ &= 41939.28 / (1 + 0.14)^1\\ &= 36,789\\ \end{align*}\]

We can repeat this for each year, and sum the present values.

year returns PV
0 -200000.00 -200000.00
1 -41939.28 -38832.67
2 -41939.28 -35956.17
3 -46939.28 -37261.91
4 -41939.28 -30826.62
5 658060.72 447865.07

The NPV of this project now 16,202, which is much lower than it was at 8%. This is because the big payday at the end of the project doesn’t mean as much in the present when those dollars are discounted back to the present at a higher rate.

When a company is considering the MARR for its own projects, it considers the cost of raising capital. What this means is that the company can raise money for its projects by selling stock in itself on the market. If the return on the investment for doing a project is less than what the company would get by simply selling its own stock, the company will lose money relative to that baseline.

The cost of capital when it is a combined sources of capital is called the weighted average cost of capital (WACC). The WACC is calculated as (Blank and Tarquin 2023a):

\[ \mathrm{WACC}= (\mathrm{equity\ fraction})\times{(\mathrm{cost\ of\ equity\ capital})}+ (\mathrm{debt\ fraction})\times{(\mathrm{cost\ of\ debt\ capital})}\\ \tag{4.20}\]

Where the cost of debt capital is the interest rate on the debt. The cost of the equity is the expected rate of return of its company shares. By selling the shares, the company will not realized those returns, in other words, the equity costs is the opportunity cost of choosing to sell their equity.

WACC Example

A large hotel company is raising money to build a new hotel for $200 million dollars. They are planning to raise $120 million by selling stocks. The stocks for the company had an average annualized ROI of 9% over the last 4 years. The remainder of the capital will be financed with a bank loan with an annual interest rate of 6%. What is the weighted cost of capital (WACC) for this project?

\[\begin{align*} \mathrm{WACC} &= (\mathrm{equity\ fraction})\times{(\mathrm{cost\ of\ equity\ capital})} \\ + & (\mathrm{debt\ fraction})\times{(\mathrm{cost\ of\ debt\ capital})}\\ &= \frac{120}{200}\times{0.09}+\frac{80}{200}\times{0.06}\\ &= 0.6\times{0.09}+0.4\times{0.06}\\ &= 0.054 + 0.024 \\ &= 0.078 \\ &= 7.8\%\\ \end{align*}\]

When you are doing NPV analysis on a complex cash flow, it is really useful to have a mechanism for understanding what is happening in each year. A cash flow diagram is simply a chart of the cash flows in each year of a project. Draw a negative bar for cash outlays (expenses, financing, etc.) and a positive bar for cash inflows (revenues, sale, etc.).

Note that you can draw this cash flow diagram for each type of cash flow, or as the net.

Multiple-year cash flow diagram

Draw cash flow diagrams for the Provo house-flipping project; include both a diagram of each element of the annual returns, and a diagram of the net returns in each year.


The charts below show these diagrams.

Figure 4.3: Itemized cash flow diagram for the Provo house-flipping project.
Figure 4.4: Net cash flow diagram for the Provo house-flipping project.
Solving NPV problems

Steps to solving NPV problems:

  1. Carefully read the problem, and identify what numbers are used for which variables. Is it an \(A\) or an \(F\)? Or an \(n\).
  2. Draw a cash flow diagram, which might help you discover any errors in step 1.
  3. Write out an equation for the NPV, using appropriate factors.
  4. Look up the factors and calculate a solution.

Appendix B includes a web application that will generate random cash flows, letting you practice solving NPV problems.

4.5 Internal Rate of Return

Learning Outcomes
  • Calculate the internal rate of return for a complex cash flow.

In Equation 4.2 we looked at how to compute the return on investment for an investement that treats all expenses and earnings as if they occur in the same year. But most built environment projects are not one-year investments. Often, people will build expensive infrastructure hoping to earn revenues over many years. But the dollars earned as revenue late in a project are not the worth the same as the dollars invested early in the project. It would be nice to know the average return on investment on a project is when the costs and revenues occur in different years.

Consider a simple project with only a present investment value \(P\) and future returns value \(F\), as in Equation 4.6. The net present value of this project is \(NPV = -P + F*P/F(i, n)\). Let’s solve this equation for the discount rate \(i\) when the NPV is zero: \[\begin{align} NPV &= -P + F*P/F(i, n) \\ 0 &= -P + \frac{F}{(1 + i)^n} \\ P &= \frac{F}{(1 + i)^n} \\ \frac{F}{P} &= ( 1 + i)^n \\ \left(\frac{F}{P}\right)^{1/n} &= (1+i) \end{align}\] which reduces to \[ i = \left(\frac{F}{P}\right)^{1/n} - 1 \tag{4.21}\]

So, there is one particular value of \(i\) that effectively sets the future returns equal to the present investment value, with \((F/P)^{-n} - 1\). This is is called the Internal Rate of Return, or the IRR. The IRR of an investment is defined as the interest rate that makes the net present value zero. Or put another way, it is the interest rate at which all future earnings are equal to the investment.

Why is this value a rate of return, or a measure of return at all? Conceptually, it shows how much our initial investment grew over the course of our project, just like ROI is supposed to. But it works mathematically as well. We can add \(P/P\) and substract \(P/P\) (effectively adding 0) inside the parentheses, \[\begin{align} i&= \left(\frac{F}{P} - \frac{P}{P}+\frac{P}{P}\right)^{1/n} - 1 \\ &= \left(\frac{F-P}{P}+1 \right)^{1/n} - 1 \\ \end{align}\] Now, let’s consider that our traditional ROI equation in Equation 4.2 can be redefined as \(ROI = \frac{F-P}{P}\) with the returns from our investment divided over the amount of the investment. This the value we have inside our rearranged Equation 4.6! \[ i= \left(ROI +1 \right)^{1/n} - 1 \tag{4.22}\] Effectively, \(i\) in this case is an annualized ROI (Beattie 2024), with each year’s returns adjusted for inflation, risk, and opportunity cost.

IRR Example

You purchased shares in an engineering firm at $5.25 per share. After 14 years the shares are worth $25.66 per share. You pay no dividends or fees. What is the total ROI for this investment? What is the annualized ROI? What is the IRR?


First, we can calculate the traditional ROI over the 14-year period:

\[\begin{align*} ROI &= \left(\frac{\mathrm{Returns}}{\mathrm{Investment}}\right) \\ &= \left(\frac{\mathrm{Capital value} - \mathrm{Initial\ Value}}{\mathrm{Initial\ Value}}\right)\\ &= \left(\frac{\$25.66 - \$5.25)}{\$5.25}\right)\\ &= 3.89 \end{align*}\]

If we divide this directly by 14 years, we would get an annual ROI of \(3.89/14 = 27\)%, but this value does not consider that the returns in some years are made of dollars that are worth less than the dollars in other years.

So, to calculate the internal rate of return we can put the 14-year ROI into Equation 4.22: \[\begin{align*} i &= \left(ROI +1 \right)^{1/n} - 1 \\ &= \left(3.89 + 1\right)^{1/14}-1 \\ &= \left(4.89\right)^{1/14}-1 \\ &= 0.012 \\ &= 12\% \\ \end{align*}\]

Or we could work directly from Equation 4.21: \[\begin{align*} i &= \left(\frac{F}{P}\right)^{1/n} - 1 \\ i &= \left(\frac{25.66}{5.25}\right)^{1/14} - 1 \\ i &= 12\% \end{align*}\]

IRR

You invest \(P\) into a savings account which yields a future value \(F\) after \(n\) years. The interest rate, \(i\), on the savings account is compounded yearly. Which of the following terms best describes \(i\)?

  • Interest rate
  • APY
  • Internal rate of return

This is a tricky question. In this simple case \(i\) can correctly be defined by each of the terms. All of these values are the same in definition. However, only IRR is available when the cash flows get complex. Please note that sometimes the IRR is also referred to as the rate of return or the ROI. For exams, and in this textbook, we will refer to the IRR as the IRR. The ROI will be used to refer to return on investment without discounting future cash flows.

The benefit of IRR is that once we have calculated the NPV of a project — no matter how complex its costs and earnings — we now have a tool to immediately calculate the implied return from this project, and we don’t have to even know what the interest rate is, because it’s something we calculate in the problem. That’s worth noting again: the NPV requires an assumed discount rate, but the IRR does not.

For example, what if you make an investment \(P\), in order to receive an annuity of \(A\) over the next \(n\) years. What is the rate of return of your investment? We can use Equation 4.12 \[\begin{align*} P &= A*\frac{(1 + i)^n -1}{i (1 + i)^n} \end{align*}\] Unfortunately, Equation 4.12 is too complex to re-arrange to solve for \(i\) by algebra. Fortunately, there is another way to solve for \(i\). We can construct the net present value of this cash flow, \[ NPV = -P + A * P/A(i, n) \] and find the interest rate that sets \(NPV = 0\). We can do this by brute force — trying values until we get the right one — or by using optimization software included in spreadsheets or other programs.

IRR Example with Factor Tables

Margot decides to pursue a PhD degree in Civil Engineering while she is working. She pays upfront $30,000 for her tuition and books at the start of her program. She then earns an additional $5,000 per year for the next 5 years while a research assistant.2 In year 5, she successfully led a team to design an earthquake resistant bridge that was a direct outcome of her thesis. The President of her engineering firm gives her a bonus of $14,746.84. What is the IRR of her doctoral investment after 5 years? Is it 6%, 8%, or 10%?


To solve for IRR, we need to find the interest rate, \(i\) that yields an NPV = 0. Let’s draw a cash flow diagram of this problem to help us set up the NPV equation.

The upfront tuition and books are a present value \(P\), the RA wages are an annuity \(A\), and the bonus she gets is a future value \(F\). So the NPV equation we need to solve is

\[0 = P + A *P/A(5, i) + F * P/F(5, i)\]

Brute force method

Let’s set up a table that will calculate this equation for different values of \(i\). The final column, NPV is the equation above using the factors on that row. You can see that with a discount rate of 8%, the NPV is effectively zero, meaning that the IRR is very close to 8%.

i P A A/P FV F/P NPV
0.06 -30000 5000 4.2124 14746.84 0.7473 2081.5156
0.08 -30000 5000 3.9927 14746.84 0.6806 0.0017
0.10 -30000 5000 3.7908 14746.84 0.6209 -1889.4387

Graphical solution

We could use a graphing calculator to solve this problem by finding the point where the NPV function with respect to the interest rate is zero.

Figure 4.5: Graphing calculator solution to the MS example.

Because the line crosses at \(i = 0.08\), the IRR is close to 8%.

Excel goal seek

We can get a more precise measure of the IRR by using a numerical solution like Goal seek in Excel. Here is a video showing how to solve the problem with goal seek:

Numerical solver

Goal seek is not the only numerical solver. In this case, I can use the R optim function which works like goal seek.

# calculate NPV for different values of i
irr_example_fn <- function(i){
  NPV <- -30000 + atop(5000, i, 5) + ftop(14746.84, i, 5)
  abs(NPV) # find smallest NPV, positive or negative
}
# find value of i that makes this function 0, within bounds
o <- optim(0.06, irr_example_fn, method = "Brent", lower = 0, upper = 1)
o$par # This is the value of i that makes NPV 0
[1] 0.08000002

Sure is close to 8%.

IRR limitations

There are situations with complex cash flows where the IRR is not unique; e.g., a complicated cash flow where costs and revenues occur in different times might result in zero NPV at 2% and at 9%. You can find these cases by plotting the IRR against the NPV and seeing if there are multiple points where the NPV is zero. In this case, you must use an alternative method to determine your project’s actual returns. Options may include an external rate of return, or a modified internal rate of return, or even just the NPV directly with a properly chosen discount rate.

Solving IRR problems

Steps to solving IRR problems:

  1. Carefully read the problem, and identify what numbers are used for which variables. Is it an \(A\) or an \(F\)? Or an \(n\)?
  2. Draw a cash flow diagram, which might help you discover any errors in step 1.
  3. Write out an equation for the NPV, using appropriate factors.
  4. Look up the factors and calculate the NPV. If your NPV is non-zero, repeat step 4 with a different discount rate.

Appendix B includes a web application that will generate random cash flows, letting you practice solving NPV and IRR problems.

4.6 Taxes

Learning Outcomes
  • Calculate the taxable income for a project in a given year.
  • Calculate depreciation of capital assets using straight-line and declining balance methods.

Taxes are “required payments of money to governments, which use the funds to provide public goods and services for the benefit of the community as a whole.” (US CFPB 2024b). In the private sector, you need to account for tax payments when you consider the profitability of your projects. In the public sector, taxes provide funding and incentivize the behavior of private sector actors.

Use accountants!

As a built environment professional, you should rely on certified accountants to understand the details of the tax code, provide advice on financial decisions, and/or file your taxes.

However, having a basic understanding of taxes and depreciation will help you make wise business and infrastructure investment decisions.

The tax a company pays in a year \(t\) is the product of its taxable income for that year and an applicable tax rate, \[ \mathrm{Taxes_t}=\mathrm{Taxable\ Income}_t \times \mathrm{Tax\ Rate} \tag{4.23}\]

Tax rate

A company has a 25% tax rate on $2 million in taxable income. What do they owe in taxes?


Beginning with Equation 4.23, \[\begin{align*} \mathrm{Taxes}&=\mathrm{Taxable\ Income} \times \mathrm{Tax\ Rate}\\ &=2,000,000 \times 0.25\\ &=500,000\\ \end{align*}\]

Effective tax rates

In the US, most companies are required to pay both state and federal taxes. Federal tax code generally allows state taxes to be deducted from federal taxes. The effective tax rate a company pays combines both of these rates into a single number,

\[ \mathrm{Effective\ Tax\ Rate}=\mathrm{State\ rate}+(1-\mathrm{State\ rate})\times(\mathrm{Federal\ rate}) \tag{4.24}\]

In this class, you should assume that tax rates given in problems are effective tax rates unless told explicitly otherwise. Common corporate effective tax rates are on the order of 25% to 40%, depending on industry and state.

Taxable income for a given year \(t\) is defined as

\[ \mathrm{Taxable Income}_t = \mathrm{Revenue}_t - \mathrm{Expenses}_t - \mathrm{Interest}_t + \mathrm{Capital\ gains}_t - \mathrm{Depreciation}_t \tag{4.25}\]

Where

  • Revenue is the money earned from operating the project.
  • Expenses is money spent during a project in order to operate it. This might include supplies, wages, and equipment repairs.
  • Interest are payments to repay the loans or debts of the project.
  • Capital gains is money earned by selling capital assets.
  • Depreciation is the loss of value in capital assets.

Note how similar Equation 4.25 is to Equation 4.1: taxable income is meant to be based on the returns of your project. There are three key differences, all related to the concept of capital assets. The basic principle of these differences is that you should be taxed for any growth in value, but that you should be able to deduct loss in value.

  1. When calculating returns in Equation 4.1, you consider the entire payment made to the bank as a “Financing” payment. In Equation 4.25, only the interest payments are deducted from taxable income. Money you pay on the principal is technically converted into value of the capital asset you bought with the loan.
  2. If you sell the asset for more than you bought it for, you pay taxes on the difference. This is different from the concept of “sale value” in Equation 4.1, which is the value that you could sell it for. With taxable income, you only pay taxes when you actually sell it.
  3. If you have an asset loses value, you can deduct this loss from your taxable income. This is called depreciation.
Capital gains tax rates

Capital gains are usually taxed at a lower rate than income, for both corporations and for individuals. This incentivizes people to hold onto assets until they mature, rather than sell the assets quickly. This is generally better for the economy. On the other hand, this policy can lead to distortionary behavior. Many company executives take their compensation in stock, and then pay a lower tax rate than if they were simply paid a salary.

In this class, we will just use a single effective tax rate for all parts of Equation 4.25.

Tax rate

Let’s go back to that house in Provo. You buy it in January 2024 for $400k with $80k invested in renovations, earn $2,000 in rent each month, and pay $400 per month in utilities. You buy the house with a loan requiring 20% down and 7.5% interest compounding annually. You sell the house at the end of 2025 (two years later) for $600k. How much do you owe on taxes in 2024 with a 28% effective tax rate? What about in 2025? Assume you make no payments on the mortgage.


Let’s start with Equation 4.25. Our utilities payments count as expenses, and we do not have depreciation yet. The interest is ?eq-interest with the proportion of the mortgage that we are paying interest on. In 2024 there are no capital gains because we still owned the house, and so had not realized any gains on it. The tax for 2024 is therefore

\[\begin{align*} \mathrm{Taxable Income}_{2024} &= \mathrm{Revenue}_{2024} - \mathrm{Expenses}_{2024} - \mathrm{Interest}_{2024} + \mathrm{Capital\ gains}_{2024} - \mathrm{Depreciation}_{2024} \\ &= (2000\times 12) - (400\times12) - (0.075\times0.8\times400000)+ 0 - 0\\ &= -4,800\\ \mathrm{Tax}_{2024} &= -4,800 * 0.28\\ &= -1,344\\ \end{align*}\]

So in 2024, we would pay zero taxes on this project.

In 2025, however, we realized gains of $200k from selling a property that we originally bought for $400k. We can now calculate the tax owed in 2024 and 2025 using Equation 4.23

\[\begin{align*} \mathrm{Taxable Income}_{2025} &= \mathrm{Revenue}_{2025} - \mathrm{Expenses}_{2025} - \mathrm{Interest}_{2025} + \mathrm{Capital\ gains}_{2025} - \mathrm{Depreciation}_{2025} \\ &= -4,800 + 200000\\ &= 195,200\\ \mathrm{Tax}_{2025} &= 195,200 * 0.28\\ &= 54,656 \end{align*}\]

Your company could be on the hook for a big tax payment in 2025. But you could reinvest this profit in new projects to avoid the capital gains.

Investment or expense?

When we introduced Equation 4.1, we talked about keeping expenses and investements separate. This is because Equation 4.25 includes expenses, but not investments. Expenses can be deducted from taxable income, but investments are not. Investments are depreciated instead.

What’s the difference? Is a truck used for your business an investment or an expense? What about the diesel fuel used to run it? And the tires? In general, the IRS classifies expenses that have a useful life of less than one year as expenses (IRS 2024b), meaning that the truck itself is a capital investment. So the purchase price of the truck cannot be deducted from your taxes, but the loss of its value is deducted through deprecation. Gas, oil changes, tires, etc. to use the truck are a business expense. But instead of tracking all of these purchases, most companies simply use a per-mile allowance set by the IRS (IRS 2024a).

As you can start to see, taxes are complicated and not always intuitive! Lesson: HIRE AN ACCOUNTANT! In this class, we will generally try to make it obvious which is which.

4.6.1 Depreciation

Many assets like stocks and real property appreciate in value over time. Other assets assets – buildings, vehicles, equipment, etc. – don’t generally accumulate value as they age. When you have a capital asset loses value over time, you can deduct the loss of that value from your taxable income as depreciation in Equation 4.25. This encourages companies to invest in new equipment and facilities, because they can recover their costs over time. There are two general methods to calculate the depreciation in a given year:

  1. Straight-line depreciation assumes that the asset loses equal value in each year until it reaches a salvage value.
  2. Declining balance depreciation assumes that the asset loses an equal proportion of its remaining value in each year.

The straight-line depreciation method assumes that the depreciation \(D\) in each year \(t\) is: \[ D_t=\frac{C-S_n}{n} \tag{4.26}\] Where

  • \(D_t\): depreciation in year \(t\)
  • \(C\): initial cost
  • \(n\): expected life of asset
  • \(S_n\): expected salvage value in year \(n\)
Straight-line truck depreciation

Your firm purchases a $50k truck and intends to use it for five years, at which point you expect to sell the truck for $20k. Using a straight-line depreciation, what is the depreciation of the truck in year two?


Starting with Equation 4.26,

\[\begin{align*} D_2&=\frac{C-S_n}{n}\\ &=\frac{$50,000-$20,000}{5}\\ &=$6,000 \end{align*}\]

Thus, $30k of the truck’s value is depreciated over 5 years. The remaining $20,000 returns to us as a capital gain in the year we sell it.

The declining balance method relies on factors — shown in Table 4.6 — to calculate the depreciation \(D\) in a given year \(t\):

\[ D_t=C\times d_{t} \tag{4.27}\]

Where

  • \(C\): initial cost
  • \(d_{t}\): depreciation rate for year {t}

Note that an asset with a ten-year depreciation timeline has eleven factors. This is because the factors assume you buy the asset in the middle of the year you buy it, and finish depreciating it halfway through the last year. Details on how the factors are calculated are in an expandable callout below.

Table 4.6: Declining Balance Depreciation Rates by Recovery Period (IRS 2024b)
Recovery Period (Years)
Year (t) 3 5 7 10
1 33.33 20 14.29 10.00
2 44.45 32 24.49 18.00
3 14.81 19.2 17.49 14.40
4 7.41 11.52 12.49 11.52
5 11.52 8.93 9.22
6 5.76 8.92 7.37
7 8.93 6.55
8 4.46 6.55
9 6.56
10 6.55
11 3.28
Factors given as percent values.
MACRS declining balance truck depreciation

Your firm purchases a $50k truck, which has a 5-year recovery period. Using the MACRS 200% declining balance method, what is the depreciation of the truck in year two?


Starting with Equation 4.27 and using the Table 4.6 factor in the five-year recovery column for year two:

\[\begin{align*} D_t&= C\times d_{t}\\ &=$50,000 * 0.32\\ &= 16000 \end{align*}\]

Why is it called the declining balance method?

Sometimes businesses might be reluctant to invest in capital projects — buildings, warehouses, heavy equipment — because capital investment is not excluded from taxable income. This would slow down the economy as people work in less efficient spaces and with older machinery.

To encourage more capital investments by private industry, the US introduced the use of accelerated depreciation methods as part of the Modified Accelerated Cost Recovery System (MACRS). This allows businesses to recoup more of their capital assets through depreciation faster than the straight line method would allow.

The accelerated depreciation methods used in MACRS uses a form of the declining balance (DB) method. In the declining balance method, the depreciation is calculated as a fixed percentage of the remaining book value. For example, in the 200% declining balance method, percent depreciation is calculated as \(d = \frac{200\%}{recovery\ period}\). For a 10-year recover period, \(d =\frac{200\%}{10}= 20\%\). The depreciation is calculating as a percentage of the book value at the end of the previous year: \(D_t = d\times{BV_{t-1}}\)(Blank and Tarquin 2023a).

Figure 4.6 compares the normalized book value, \(BV_t/C\), for the straight-line method, a true 200% declining balance method and the MACRS 200% declining balance method over a 10-year return period. Using a true declining balance method the book value will never reach zero. Thus, the MACRS 200% declining balance method switches to a straight-line method when the straight-line results in a larger depreciation than the declining balance method. In a 10-year recovery with a 200% declining balance, this occurs at age 6 as shown in Figure 4.6.

Figure 4.6: Comparison of depreciation methods over 10 years using Half-Year Convention

The IRS (2024b) simplifies the depreciation calculations by providing tables of MACRS depreciation rates, \(d_{t,p}\), by different methods, years \(t\), recovery periods \(p\), and for the season when the asset began service. In addition, MACRS requires the book value to depreciate decrease all the way to $0 at the end of the recovery period for both straight-line and declining balance methods.

Note there are 11 years of depreciation factors for a 10-year recovery period in Table 4.6. This is because a half-year convention is used, meaning that we assume the asset is placed into service half-way through the first year \((t=0.5\ years)\), and ends half-way through the eleventh year \((t=10.5\ years)\) as shown in Figure 4.6. The first and eleventh year depreciation factors are 50% smaller than if they were full years.

In this course we provide depreciation factors for the MACRS 200% declining balance method using the half-year convention in Table 4.6. All the homework and exam problems regarding MACRS will use this table. The IRS (2024b) dictates the recovery periods for different classes of assets.3 The recovery period will be given you in your homework and exam problems. In your career you will need to consult IRS (2024b) or a certified accountant.

MACRS

Technically, MACRS defines both the straight-line and various declining balance methods depending on rates of depreciation and the seasons when the asset enters service, but many sources — including FE and PE reference manuals — use MACRS to refer to one particular declining balance method only. As in, they define two methods, straight-line recovery and MACRS. Pay attention to the context of the problem!

An important concept related to depreciation is the book value of the asset, or how much an asset contribute’s to your company’s overall value in a particular year \(t\). This is defined as

\[ BV_t=C-\sum_{n=1}^t{D_n} \tag{4.28}\]

Where

  • \(BV_t\): Book Value in year \(t\)
  • \(C\): initial cost
  • \(n\): number of years in recovery period
  • \(D_n\): depreciation in year \(n\)

Note that the book value is different from the market value — what the asset would likely sell for. For example, a the market value of a warehouse could appreciate from the purchase price due to rising real-estate prices, but for tax purposes the book value could decrease from the initial value, allowing the owner to take tax deductions on the decline in value of the warehouse. (Blank and Tarquin 2023a).

Book value

For the $50,000 truck with a $20,000 salvage value and a 5-year recovery period, what is the book value of this truck at the end of year two by the straight-line recovery method? What about by the declining balance method?


For the straight line method, we have two years of depreciation using Equation 4.26

\[\begin{align*} D_t&=\frac{C-S_n}{n}\\ &=\frac{$50,000-$20,000}{5}\\ &=$6,000 \end{align*}\]

so the book value of this, using Equation 4.28:

\[\begin{align*} BV_n&=C-\sum_{n=0}^t{D_n}\\ &=50000 - (6000 + 6000)\\ &=$38,000 \end{align*}\]

In the declining balance method, we need to figure out the depreciation in year one and year two using Equation 4.27:

\[\begin{align*} D_t&= C\times d_{t}\\ D_1 &= $50,000 * 0.2\\ &= 10,000\\ D_2 &=$50,000 * 0.32\\ &= 16,000 \end{align*}\]

And so the book value of the truck via this method, using Equation 4.28:

\[\begin{align*} BV_n&=C-\sum_{n=0}^t{D_n}\\ &=50000 - (10000 + 16000)\\ &=$24,000 \end{align*}\]

A big difference! If we had done one more year, the difference would not have been quite as large.

Which depreciation method should I use for my project?

The declining balance method will allow you claim larger deductions from your investments sooner. You can then use the money you save in taxes to recoup the costs of your investment, help pay off your loans of your capital investment, or invest in other projects.

If you have many other tax deductions in the earlier years of the recovery period, you may elect for one of the other methods that gives you larger tax deductions in later years of the recovery period.

4.7 Project Assessment

Learning Outcomes
  • Identify preferred project alternatives using net present value, internal rate of return, and benefit/cost analysis.

In the previous section on returns, we looked at project evaluation largely as a binary consideration: is the IRR greater than the MARR? Or, is the NPV positive?

It is rare to only have one course of action in an investment. More typically, there are multiple different strategies or alternatives that you need to weigh against each other. In this section, we will discuss how to comparatively evaluate projects with different timelines, discount rates, and other variables.

4.7.1 NPV and IRR

NPV and IRR are both important methods to compare projects. These measures can sometimes identify different preferred alternatives, however this is not always the case as shown in the following example.

Example

Four different alternative highway maintenance regimens — plus a “do-nothing” alternative — are being considered. The present value of the long-run benefits (earnings) and costs (investments) are given in the table below. Calculate the NPV and IRR for each alternative. Assume a discount rate of 8%.

bc <- tibble(
  Alternative = c("Do Nothing", "A", "B", "C", "D"),
  Benefit = c(0, 24, 11, 41, 43),
  Cost = c(2, 7, 9, 17, 32),
)
tt(bc)
Alternative Benefit Cost
Do Nothing 0 2
A 24 7
B 11 9
C 41 17
D 43 32

This is a tricky problem, because there are two different discount rates: the discount rate for the analysis, and the IRR. The long-run benefits are a perpetual annuity, with a present value of \(A/i\) that is given in the problem. This implies that the benefit’s equivalent annuity value is \(A = P * i\) or \(\mathrm{Benefit}\times 0.08\). For alternative A,

\[\begin{align*} \mathrm{Benefits (P)} &= \mathrm{Benefits (A)}/i\\ \mathrm{Benefits (A)} &= P * i\\ &= 24* 0.08\\ &= 1.92 \end{align*}\]

To get the IRR, we would need to find the discount rate at which the present value of the perpetual annuity is equal to the construction costs present value. \[\begin{align*} \mathrm{Construction} &= \mathrm{Benefits (P)}\\ \mathrm{Construction} &= A / i_{irr}\\ i_{irr} &= \frac{A }{\mathrm{Construction}}\\ &= \frac{1.92}{7}\\ &= 0.274\\ \end{align*}\]

The NPV is much easier, and is simply the benefits minus the costs. For all options and with IRR given as a percent,

Alternative Benefit Cost IRR NPV
Do Nothing 0 2 0 -2
A 24 7 27.43 17
B 11 9 9.78 2
C 41 17 19.29 24
D 43 32 10.75 11

Based on IRR, the preferred alternative is \(A\), but based on NPV the preferred alternative is \(C\).

Think

Should you use NPV or IRR to prioritize projects?

That depends. If the projects are mutually exclusive (e.g. there are different alternatives for the same project, and you only can pick one alternative), then it is recommended to select the project with the largest net present value. (Blank and Tarquin 2023b).

If the projects are independent from one another (e.g doing project A doesn’t stop you from doing project B) then a good approach is to rank the projects by the rate of return. (Blank and Tarquin 2023c). First do the project with the best rate of return, if you have sufficient remaining funds, then do the project with the next best rate of return, and so on. Other methods to rank independent projects projects given budget constraints are discussed in (Blank and Tarquin 2023c).

4.7.2 Benefit Cost Analysis

Private projects often will use the rate of return or the net present value to select between alternatives. This evaluates how much returns will return to the firm. For governmental or charitable non-profit organizations may want to pick a project that provides the most benefits to the public rather than the highest returns to the company. Benefit cost analyses (BCA) balances the benefits and costs of a project incurred to the public. Benefit cost analysis is also referred to as Cost-Benefit Analysis (CBA). BCA uses two different metrics, net benefits and benefit cost ratio (B/C). (FHWA 2020)

4.7.2.1 Net Benefits

The net benefits are similar to the net present value, and are calculated as the present value of the benefits subtracted by the net costs, as shown in the equation Equation 4.29.

\[ \mathrm{Net\ Benefit}s=\mathrm{Present\ Value\ of\ Benefits} - \mathrm{Present\ Value\ of\ Costs} \] Expressed mathematically as:

\[ \mathrm{Net\ Benefits}=\sum_{t=0}^{n} \frac{B_t}{(1+i)^t}-\sum_{t=0}^{n} \frac{C_t}{(1+i)^t} \tag{4.29}\]

Where

  • \(B_t\): Benefits at time \(t\)
  • \(C_t\): Costs at time \(t\)
  • \(i\): discount rate
  • \(t\): period of time

Benefits could include revenue, (such as tolls for a highway project) or funds saved (such as lower energy costs). Costs include the capital costs to build the project, operating and maintenance costs, and interest payments. With large multi-year infrastructure projects with long term impacts on the public, we account for the time value of money when calculating net benefits as shown in Equation 4.29.

The benefit and the costs can be external to the organization building of funding the project. For example, the Federal Highway Administration (FHWA) lists the following as potential benefits and costs that can be included in an analysis of a highway project.(FHWA 2020)

  • Travel time (and the reliability of travel time)
  • Crashes
  • Fuel use
  • Vehicle operating costs
  • Emissions/air quality
  • Agency efficiency

In addition, the benefits could include lower costs due less risk of damage from a natural disaster (for a new flood levee or culvert). To include these external costs in a benefit-cost analysis, we need to be able to monetize these benefits and costs. As expected, many of the external or preventative benefits and costs are difficult to monetize. Economists have developed prices for some of these intangible costs, including the value of increased safety, by putting a value on human life.

Think

Is it ethical to put a price on a human life when evaluating infrastructure projects?

Imagine what would happen if we planned all projects to try to eliminate all risks to zero. Despite our best intentions, we can never completely reduce the risks of dying due to building failure, traffic crashes, or exposure to harmful pollutants. Even if we did, we would not accept the costs of such actions. e.g. if everyone traveled at a max speed of 20 mph, we would likely save lives from traffic accidents, but the cost of the extra travel time would be too high.

Federal agencies such as the Federal Highway Administration (FHWA), and the US Environmental Protection Agency (US EPA) use the value of the statistical life (VSL) in benefit cost analyses of projects, programs, and rule makings. By using the VSL, we can monetize the benefits of increased safety or decreased exposure to pollution, to then choose an acceptable amount of risk by balancing both cost and safety.

The US EPA describes VSL as (EPA 2014)

The EPA does not place a dollar value on individual lives. Rather, when conducting a benefit-cost analysis of new environmental policies, the Agency uses estimates of how much people are willing to pay for small reductions in their risks of dying from adverse health conditions that may be caused by environmental pollution.

For example, the US EPA used a VSL of $11 million dollars in a cost-benefit analysis of a proposed rule to lower emissions from heavy-duty trucks. (US EPA 2022)

You can quantify the benefits from lives saved due to increased safety or less pollution exposure in terms of reduced risk from a baseline condition. The risk for a certain negative outcome (such as death or injury) is calculated using Equation 4.30.

\[ \mathrm{Risk} = \mathrm{number\ of\ people}\times\mathrm{probability}\times\mathrm{impact} \tag{4.30}\]

Where

  • number of people: number of people potentially impacted by the negative outcome
  • probability: probability of the negative outcome occurring to each person
  • impact: the cost of the negative outcome occurring to a person

The benefit is then calculated as:

\[ \mathrm{Benefit}_{alternative} = \mathrm{Risk}_{baseline}-\mathrm{Risk}_{alternative} \tag{4.31}\]

4.7.2.2 Benefit Cost ratio

The second metric we use in benefit cost analyses is the benefit to cost ratio, \(\ (B/C)\). The benefit cost ratio is similar to the ROI, in that it considers the benefits compared to the costs.

\[ \mathrm{Benefit\ Cost\ Ratio} (B/C)=\frac{\mathrm{Present\ Value\ of\ Benefits}}{\mathrm{Present\ Value\ of\ Costs}} \tag{4.32}\]

If the ratio \(B/C > 1\), then the project is feasible. If the \(B/C <1\) the costs outweigh the benefits and the project is not recommended. If a project has a higher \(B/C\) ratio than another project, it could be more attractive than other alternatives.

Example

The present value of benefits and costs of four alternative highway maintenance projects (plus a “do nothing” alternative) are given below. Calculate the \(B/C\) ratios.

Alternative Benefit Cost B/C
Do Nothing 0 2 0.00
A 24 7 3.43
B 11 9 1.22
C 41 17 2.41
D 43 32 1.34

Using the B/C ratio, alternative \(A\) is the best option.

Do you use the Net benefits or use the B/C ratio in prioritizing projects? Both provide useful information, however you may want to consider using these metrics the same way we recommend using NPV and IRR. If you projects are mutually exclusive, you should pick the alternative that maximizes the net benefits. When you are evaluating many independent projects, you may want to prioritize the projects with the highest B/C ratio.

Note

In all of the examples we have covered, the benefits and costs of the projects were taken as given. In the real-world, almost all of the revenues and costs can only be estimated (save perhaps a loan payment which may be known). You should consider how confident you are in those estimates when conducting a financial or benefit cost analysis of a project. One way to do that is using an evaluation matrix discussed in the next section.

4.7.3 Evaluation Matrices

While benefit cost analyses are useful, decision makers often consider additional factors regarding large infrastructure projects. Large public projects have benefits and costs that occur on a wide spectrum of different dimensions. It can be difficult or impossible to monetize all benefits and costs in a BCA. Also, in a simple cost benefit analysis, we don’t consider social justice, or the equal sharing of costs and benefits (e.g. Who is benefiting the most from this project?, Who is most adversely impacted by this project?). We can use the triple-bottom line discussed in Chapter1 as a guide in making decisions, but within each of these dimensions can be multiple different variables that require consideration. A common method to put these variables into one decision making framework is by using an alternatives evaluation matrix.4 To create this matrix:

  1. Decide which elements of a project, in terms of benefits and costs or other outcomes need to be considered. This may involve public input.
  2. Develop a scoring system \(b\) for each element. This is often a score of 1 to 5 or a grade of A to F or some other categorical measure.
  3. Develop weights \(w\) for each element, again with public input.
  4. Calculate the weighted score of each alternative as \(S_a= \sum_e w_e*b_{ea}\) where \(S\) is the total weighted score for the alternative, \(w_e\) is the weight of each element \(e\), and \(b\) is the score of within that element for each alternative.

Figure 4.7 shows a project evaluation matrix from the Utah Transit Authority’s Point of the Mountain alternatives analysis. UTA has developed five different alternatives to provide high-frequency transit to Lehi and the site currently occupied by the Utah State Prison, using different combinations of light rail extensions and new BRT service. These five alternatives are each evaluated on a five-point scale applied to 19 different measures grouped into five general categories:

  • Transit System Performance
  • Access and Mobility
  • Land Use
  • Cost and Constructability
  • Natural and Built Environment
Figure 4.7: Point of the Mountain Transit Study alternatives analysis.

You can see in the figure how each alternative generally performs. The EW Connections alternative scores the best in terms of cost, but it performs poorly in terms of transit speed and reliability. The LRT East and BRT East alternatives have similar profiles, but the BRT option trades a bit of speed and reliability for a lower cost.

When conducted in this way, a number of different factors besides pure cost and benefit are allowed to contribute to the overall project evaluation. There is also a risk, however, that this method can become purely subjective if care is not taken to avoid pre-determining the outcome.

Unit Summary

The time value of money means that $100 now is worth more than $100 in the future because of risk, inflation, and opportunity cost. This makes interest a powerful tool in funding projects with things like mortgages, bonds, sinking funds, and toll-based financing. Cash flow diagrams provide an easy way to organize the cash flows of projects over long periods of time. Using equivalence equations for present value, future value, and annuities allows us to calculate the net present value (NPV) from a cash flow diagram, which determines if a project will be profitable. We must pick an appropriate discount rate in order to correctly calculate the present value of future cash flows and to meet our minimum acceptable rate of return (MARR). We can also calculate the internal rate of return for complex cash flows from infrastructure projects.

Ultimately, though, decisions cannot be based on finances alone. They must also incorporate costs and benefits that do not have monetary values, either by determining a value for them or by using a suitable weighting system for different categories. Sustainable infrastructure can only be achieved if all of these factors are considered.

  • annuity (A): a series of equal payments made over time
  • bond: financial tool in which an investor loans a sum of money to an organization, and the borrower pays annual interest on the loan until the end date of the bond, at which point they pay back the face value
  • book value: the initial cost of an asset minus total depreciation
  • cash flow diagram: a graphical display of cash inflows and outflows over time
  • compounding frequency: the frequency with which the interest on a loan is re-applied to the principal
  • depreciation: the value of an asset lost over time due to use, found using methods like straight-line or MACRS
  • discount rate: an interest rate used to determine the present value of a future cash flow
  • external rate of return (ERR): the discount rate at which the present value of investments is equal to the future value of earnings
  • factor tables: tool for converting cash flows (PV,FV,A,G) into equivalent time values of money
  • future value (FV): the equivalent future worth of a sum of money or series of payments
  • gradient (G): a series of equally increasing payments made over time
  • inflation: the increase in price for goods and services over time
  • interest: money paid by a borrower to a lender in exchange for the use of their money
  • internal rate of return (IRR): the discount rate that makes the NPV of a project equal to zero
  • minimum acceptable rate of return (MARR): the lowest rate of return that a project must earn in order to be worthwhile to an investor
  • mortgage: a loan to purchase property using that property as collateral, repaid in regular periodic amounts
  • net present value (NPV): the equivalent present value of all future cash flows
  • opportunity cost: the potential benefits that are lost when one option is chosen over another
  • present value (PV): the present worth of a sum of money or series of payments
  • project assessment: comparing projects using methods such as NPV, ROI, B/C, and incremental B/C
  • project evaluation matrix: a tool to compare several alternatives across an array of quantitative and qualitative criteria
  • refinancing: taking out a second loan at a lower interest rate to pay off an original mortgage
  • return on investment (ROI): the ratio of the equivalent annual earnings to the total investment
  • risk: the chance that an investment will be less profitable than expected, including the possibility of losing some or all of the original money
  • sinking funds: a fund where smaller amounts of money are put aside regularly to pay for some larger expense in the future
  • time value of money: the concept that money now is worth more than the same amount of money later because of risk, inflation, and opportunity cost
  • toll-based financing: loans to build infrastructure are repaid using future revenue from tolls and service fees
  • zoning: laws that specify what types of projects can be built in certain areas

Homework

Problem Set: Returns and ROI

HW 1: Investments and Returns

A corporation wants to build a renewable energy project with an expected capital investment of $750,000. During the life of the project, it is expected to generate $2 Million in revenue and cost $500,000 to operate. At the end of the project you expect to sell all remaining assets for $300,000. What are the returns and ROI for this project?

HW 2: Excavation Expansion

You own an excavation company. You are considering buying an additional excavator for $125,000 and hiring someone to operate it for one year. You will keep the excavator at the end of the year. With the excavator, you estimate your additional annual revenue and expenses to be:

Revenue Fuel Maintenance Insurance Operator Wages
$120,000 $10,000 $10,000 $15,000 $50,000

What are the returns and ROI for buying the excavator?

HW 3: Excavation with a Loan

Now assume that you take out a loan to pay for the excavator. You have a 20% down payment and will pay $6,000 in interest. You don’t need to pay back the loan this year. All of the other expenses remain the same. What are the returns and ROI for buying the excavator with a loan?

HW 4: Excavation expansion: yes or no?

If you were in charge of this excavation company, should you expand by acquiring an additional excavator? Should you use debt and a bank loan to help make this expansion? What would be the risks of taking on debt? Write a short response below.

Problem Set: Taxes and Depreciation

HW 5: Book values

A company purchases a bulldozer for $200,000 and expects a salvage value of $30,000 at the end of the 7-year recovery period. Using both the straight-line and declining balance depreciation methods, calculate the depreciation and book value of the asset at the end of each year of the recovery period. Which method will have a lower tax burden in year 6, all else equal?

HW 6: Excavator Depreciation

Reconsider the excavator problem in HW 4 (where you took out the loan), but include the depreciation of your excavator and the taxes you need to pay to operate. Assume that the excavator has a 10-year lifetime with a salvage value of $10,000, and use straight-line depreciation. Use a 33% effective tax rate.

  1. What is the annual depreciation value?
  2. Re-calculate the annual returns and the simple payback period.
  3. Re-calculate the 1-year ROI considering the excavator depreciation.
HW 7: A fleet of excavators

Your company purchased an excavator in 2019, 2021, and 2022; each excavator cost $125,000. What is the total book value of all of your excavators in 2025 by the declining balance method? Construction equipment has a five-year recovery period.

Problem Set: Time Value of Money

HW 8: Time value F from P

A $5,000 investment earns 6% per year. What will be the value of this investment in 15 years if:

  1. The investment is compounded annually?
  2. The investment is compounded monthly?
HW 9: Time value P from F

When you were born, your grandparents purchased shares in a mutual fund paying 8% interest per year compounded annually, hoping that this investment would pay for your college tuition (lucky!). Assuming you are at BYU for eight semesters beginning when you are 19, how much should they have invested?

Assumptions

This problem requires you to make assumptions. There is not a single correct answer as different assumptions can be valid. Document your assumptions, and show your work.

HW 10: Comparing F

Sarah and Brian both invest in a retirement fund. Sarah invests $15,000 at age 30, while Brian invests $40,000 at age 50. Both accounts earn 8% interest per year, compounded annually.

  1. How much each will they each have at age 65?
  2. How much would Brian need to invest at age 50 to have the same amount as Sarah by age 65?
HW 11: Simple Uncle Shark

You borrow $20,000 from your uncle to help pay for four years of college (because your grandparents didn’t buy you a mutual fund…). You agree to a simple interest loan with an annual interest rate of 6% on the remaining principal owed at the end of each year. Each summer in college (before the end of the year) you work in his company and earn $4,000 which you use to pay down the loan principal. You then pay the entire loan off with your first out-of college paycheck at the beginning of year 5.

  1. How much total interest do you pay your uncle over the course of the loan?
  2. What is the payoff amount?

Include a table like the one below tracking your loan (you might find it helpful to have other columns as well).

Year Principal Interest Loan Balance (End of Year)
1
2
3
4
HW 12: Compound Uncle Shark

Repeat the previous problem, but the loan is compounded annually. That is, the interest is calculated on the entire remaining balance rather than just the principal amount.

Problem Set: Annuities and Gradients

Tip

I recommend solving the problems in this problem set primarily with the factor tables in Appendix A, so you can get used to using them.

HW 13: Car Maintenance

Frank’s parents give him an old car that will last for 10 more years as long as he keeps repairing it. The car needs $500 worth of repairs the first year, and the maintenance costs will increase by $50 each year afterwards. How much money does Frank need to invest now at an 7% interest rate to pay for the next 10 years of maintenance on the car? Draw a cash flow diagram as part of your solution.

HW 14: Stock Market

You decide to invest in the US stock market, which has a historic return of 10% per year.

  1. How much would you need to invest each year to have $1,000,000 by age 65 if you started saving at age 25?
  2. How much would you need to invest each year to have $1,000,000 if you started at age 45?
HW 15: Depreciation in the present

You buy an excavator for $125,000 which has a 5-year recovery period and you expect to salvage the excavator for $25,000. What is the present value of all of the depreciation expenses if you use a straight line depreciation and assume a 6% discount rate? Include a cash flow diagram in your answer.

HW 16: Home Loan

You are buying a home for $430,000. Your 30-year mortgage has a 6.28% annual interest rate (compounded monthly) and requires a 20% down payment to secure.

  1. What is the monthly payment? Recall that \(i/k\) is the periodic interest rate.
  2. What is the total amount paid?
  3. For each month, calculate the amount of the payment that goes to interest and the amount that goes to principal. Create a plot showing these amounts over the entire course of the loan.
Help

Each month, your monthly payment includes part interest and part payment on your principal. If you pay all the interest that accrues each month, then any amount left over from your monthly payment will apply to the principal.

Set up a spreadsheet or computer program that calculates the amount paid to interest and to principal in each month of the 30-year mortgage. You should include example calculations and the top few rows of the table in your homework submission, but do not need to include the entire 360-line spreadsheet.

Also: if you have done this correctly, you will pay off the loan with your last payment.

HW 17: Home Loan Payoff

Consider the same information as the previous problem. What happens if you are able to pay an additional $200 each month?

  1. After how many years do you pay off the mortgage?
  2. How much total money do you pay?
  3. How much money do you save compared to the previous problem?

It is not necessary to include the graph again.

Problem Set: Equivalence

HW 18: Water lines

You are considering signing a contract to install water lines in a development project with a 5-year construction timeline. You expect your annual costs to be $400,000/year. The developer provides two options for your company’s payment.

  • Option 1: The developer pays you $1,000,000 now (year 0), and $2,000,000 at the end of the project in 5 years.
  • Option 2: The developer pays you $4,000,000 at the end of the project (in 5 years).
  1. Draw/graph a cash flow diagram of both options.
  2. Assume your company uses an annual discount rate of 12%. Calculate the present value for each of the payment options.
  3. Which is the preferred option using the net present value (NPV)?
  4. What other financial considerations are there that are not expressed in the NPV?
HW 19: Construction Company Present Value

You are a project manager for a construction company, and you are evaluating the potential investment in a new piece of heavy machinery. The initial cost of the machinery is $150,000. You expect this machinery to generate additional annual revenues of $45,000 for the next 5 years. At the end of the 5 years, the machinery will have a salvage value of $10,000. The company’s expected rate of return for their investments is 8%.

  1. Calculate the Present Value of Future Revenues: Using the company’s expected rate of return of 8%, calculate the present value (P) of the additional annual revenues generated by the machinery over the next 5 years.

  2. Calculate the Present Value of the Salvage Value: Calculate the present value (PV) of the salvage value of the machinery at the end of 5 years using the company’s required rate of return of 8%.

  3. Calculate the Present Value of the Revenue and the Salvage Value: Combine the present value of the future revenues and the present value of the salvage value to determine the total present value (PV) of the revenues.

  4. Determine the Net Present Value (NPV): Calculate the net present value (NPV) of the investment by subtracting the investment cost of the machinery from the present value of the revenue and salvage value calculated in question 3.

  5. Evaluate the Investment Decision: Based on the NPV calculated in question 4, determine whether the company should proceed with the investment in the new machinery. Explain your reasoning.

HW 20: Air Conditioner

Alissa wants to install a new $9,000 air conditioning system. Because it is more energy efficient, the system would save $1,400 per year in electricity costs. Assume the air conditioner is installed in year 0, and savings begin with year 1.

  1. Without accounting for the time-value of money, what is the payback period?
  2. Assuming a discount rate of 7%, how long will it take for the air conditioning system to pay for itself? Assume the savings compound annually. Hint: Find the number of years where the net present value is 0. This problem can be solved in multiple ways: algebraically manipulating the formula to solve for \(n\), using goal seek to change \(n\), or plotting \(n\) vs. \(P\) in a table.
  3. Draw a cash flow diagram for each of the above parts. Make sure to label your axis and which diagram comes from which part.
HW 21: Bonds

Ben can buy a bond with a face value of $1,000 paying at 6% interest for five more years.

  1. Draw or graph a cash flow diagram for the bond.
  2. What is the present value of this bond if Ben’s personal discount rate is 5%?
  3. What is the present value at a 7% discount rate?

Note: to solve this problem, first draw the cash flow diagram for the bond. Then, determine the present value of the bonds using the different discount rates.

Problem Set: Internal Rate of Return

HW 22: Pavilion to rent

In 2019, you built a pavilion to rent for special events $15,000 and started operations in 2020. Each year you operate, you incur $100 in expenses. In 2020, you made no money because of the pandemic. But in 2021 you earned $1,000, and grew your business by an $1000 each year after (e.g. $2000 in 2022, $3000 in 2023, etc.). At the end of 2024, you sold the pavilion for $15,796.68.

  1. Draw a cash flow diagram of this project.
  2. Calculate the NPV of this investment given discount rates of 10%, 12%, and 18%.
  3. What is the IRR of this investment?
HW 23: Dock

You are considering building a new dock at a port. There are two options for the dock. Dock A is smaller, will cost $70 Million dollars, and will generate returns of $24 million dollars/year for the next 10 years. Dock B is larger. It will cost $170 Million dollars and generate $41 million dollars per year for the next 10 years.

  1. The port authority uses a discount rate of 8% to evaluate capital investments. What is the net present value of both options using the 8% discount rate?
  2. What is the internal rate of return for both options?
  3. Which dock would you recommend building? Why?
HW 24: Varying Incomes

In 2010, you made a $45,000 investment in new construction equipment, which you expected to generate revenue of $10,000 per year for the next ten years (2011 through 2020), on $3,000 of annual expenses. In reality, the revenue was the values in the actual column of the table below:

year expenses expected actual
2011 3000 10000 7000
2012 3000 10000 10000
2013 3000 10000 13000
2014 3000 10000 18000
2015 3000 10000 11000
2016 3000 10000 2000
2017 3000 10000 8000
2018 3000 10000 12000
2019 3000 10000 7000
2020 3000 10000 14000
  1. Calculate the IRR for the expected project as well as what actually happened. Did things go better or worse than what you expected?
  2. Comment on what might happen in 2016 if this project was financed through a bank.
HW 25: The Big Kahuna
Difficult problem

This problem ties together almost everything you have learned in this unit. When you understand how to solve this problem, then you should be well-prepared for the test and to solve related problems in your career.

Advice to solve: clearly read the problem, and take each element in steps. Set up a spreadsheet to track each year’s returns, taxable income, and any values used to calculate those elements. As always, include example calculations in your homework response, alongside a replication of your spreadsheet.

Your company is looking to build a new incinerator that will generate electricity by burning household waste and thereby diverting trash from landfills. Someone in your office recommended calling this incinerator “The Big Kahuna” and no one else had any better ideas.

Each year you operate, you will generate electricity worth $1.5 million, and incur expenses of $400,000. Your incinerator will go online halfway through 2026, and will stop operations at the end of 2035 (i.e., 2026 will only have half the revenue and half the expenses but 2035 will have a full year).

The incinerator costs $3 million dollars, and you will finance its purchase with a bank loan offered at 6.5% annual interest compounded annually and 20% down, paid back over the next ten years (down payment in 2025, payments starting in 2026).

Incinerators like this one have a seven-year recovery period using the MACRS declining balance method. You also expect to salvage the equipment for 500,000 at the end of 2035. You pay a corporate tax rate of 28% on your taxable income, and your company has a MARR of 12%.

  1. Calculate the NPV of this project using a 12% discount rate.
  2. Calculate the IRR of this project.
Range of answers

If you have done this problem correctly, you should get an NPV in the neighborhood of $2.5 Million with an IRR between 50% and 100%.

HW 26: Self-financing the Big Kahuna

When you are about to finance the loan, one of the members of your board calls you up and says he would rather the company self-finance the incinerator purchase, to keep the company out of debt. Is this a good idea?

Tip

The best way to solve this problem is to simply copy your spreadsheet from the previous problem, and change it so that the entire cost of the incinerator comes up front, and remove the finance payments. Calculate the NPV and IRR, and use that information to tell your board member what you think the company should do.

Problem Set: Project Assessment

HW 27: Arizona Traffic Projects

You are evaluating the profitability of different traffic projects for the Arizona Department of Transportation (AzDOT). You assume that these projects will last a long time, and for simplicity you assume that the benefits can be projected for perpetuity (forever). The construction costs, and the annual returns from each project are listed in the table below. Assume that construction occurs at age 0 of the project, and the returns occur starting in year 1 for perpetuity.

Project Construction Cost Annual Returns [M$] Present Value (Returns) Net Benefits B/C IRR
A 20 1.8
B 82 6.0
C 120 10.0
D 140 10.5

AzDOT uses a discount rate of 4% for all projects.

  1. Complete the table with these calculations. Show your work with an example calculation.
  1. Calculate the present value of the returns
  2. Calculate the net benefits
  3. Calculate the benefit/cost ratio
  4. Calculate the IRR (%)
  1. Assume that projects A through D are for different independent traffic projects throughout Arizona. Your supervisor asks you to recommend which projects should be built this year given a budget of $140 Million. Which project(s) do you recommend? Which financial metric did you use to develop your recommendation? Hint: See the “Think” box in Section 4.7.1.

  2. Assume that projects A through D are different alternatives for the same traffic project. This means that you can only do one of the projects. Again you have a budget for this project of $140 Million. Your supervisor asks you to recommend one project. Which financial metric do you recommend to use? Why? What are your net benefits?

HW 28: Traffic Engineer in Provo City

You are a traffic engineer for Provo City. You recently conducted a safety analysis of pedestrian crossings. One of the pedestrian crossings was identified as University Avenue between the old Provo High school and the BYU Indoor training facility.

The pedestrian fatality rate was estimated to be 0.01 fatalities per 100,000 pedestrians. You estimate that 200,000 pedestrians will use the pedestrian crossing per year. Assume that Provo City uses a value of a statistical life of $11,000,000.

You have developed two different proposals for the city. Option 1 is an elevated walkway, and Option 2 is an improved crosswalk with flashing lights. You have conducted a safety analysis of both options. Option 1 is the safest option, but the most expensive. Option 2 improves the safety, but is much less expensive. The lifetime of both projects is assumed to be 30 years.

Project Fatality Probability per 100,000 Pedestrians Construction Costs
baseline 0.0100 0
Option 1 0.0010 4,000,000
Option 2 0.0075 600,000
  1. Calculate the annual cost of the risk of pedestrian fatalities in dollars, assuming 200,000 annual pedestrians, estimated pedestrian fatality rates, and the value of a statistical life. From the baseline scenario, and the two proposals. Use the definition of risk found in Equation 4.30
  2. Calculate the benefits for each of the two proposals as the reduced risk of pedestrian fatalities over the 30-year life-time of the pedestrian crossings. Calculate the benefits as the reduction in risk from the baseline scenario. Calculate the present value of benefits over the 30-year lifetime of the pedestrian crossings. Use a discount rate of 2%.5
  3. Calculate the net benefits (Benefits – Construction Costs) for the lifetime of the project. Which project has the higher net benefits?
  4. Calculate the benefit/cost ratio for the lifetime of the project. Which project has a higher benefit/cost ratio?
  5. From the financial perspective, are both options worth considering? Why?
  6. Which project would you recommend? Why?

Problem Set: Multi-criteria


  1. You can also see this as an algebraic operation, \(F = P * F/P (i, n)\), where the factor you want \(F\) is isolated by dividing \(P/P\).↩︎

  2. This isn’t how PhDs work in engineering, where your tuition is usually paid by your research grants.↩︎

  3. For example, tractor units have a recovery period of 3 years. Vehicles have a recovery periods of 5 years. Office furniture, railroad tracks, and natural gas lines are 7 years, land improvements, electric transmission properties are 15 years. Water treatment and water distribution properties are 25-years. As you can see the recovery periods only seem somewhat related to the actual life-time of the assets.(IRS 2024b)↩︎

  4. This is sometimes called a Kepner-Tregoe (KT) matrix after the authors who proposed it as a rational process for decision making (Kepner and Tregoe 1981).↩︎

  5. When we conduct a lifecycle analysis, shouldn’t we calculate the future value of cost and benefits to account for inflation, and then discount it back to the present value? In other words, if a VSL is worth $11 million today, shouldn’t it be worth even more in the future? The White House’s guidance on conducting lifecycle analysis recommends using constant-dollar values for future costs, and use a discount rate that has the inflation effect removed, called the real discount rate. The nominal discount rate is an estimate of the time-value of money, including the impact of inflation. For regulatory analysis, the White House recommends estimating the nominal discount rate from US treasury returns (OMB 2023). The real discount rate is calculated by subtracting the impact of inflation rate from the nominal discount rate. For example, if the nominal discount rate is 4%, and inflation is 2%, then the real discount rate is approximately 2% (See ?eq-discount). The net present value will be the same if your future costs include an inflation rate of 2%, and you discount using the nominal rate of 4%, as a case where future costs are expressed in constant-dollars, and you discount back to the future using the 2% real discount rate.↩︎